5x+2/3(x+3)=1/4(x-1)

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Solution for 5x+2/3(x+3)=1/4(x-1) equation: 



5x+2/3(x+3)=1/4(x-1)

We move all terms to the left:

5x+2/3(x+3)-(1/4(x-1))=0



Domain of the equation: 3(x+3)!=0

x∈R





Domain of the equation: 4(x-1))!=0

x∈R



We calculate fractions


5x+(8xx/(3(x+3)*4(x-1)))+(-3xx/(3(x+3)*4(x-1)))=0



We calculate terms in parentheses: +(8xx/(3(x+3)*4(x-1))), so:

8xx/(3(x+3)*4(x-1))

We multiply all the terms by the denominator


8xx

Back to the equation:

+(8xx)





We calculate terms in parentheses: +(-3xx/(3(x+3)*4(x-1))), so:

-3xx/(3(x+3)*4(x-1))

We multiply all the terms by the denominator


-3xx

Back to the equation:

+(-3xx)



We get rid of parentheses

5x+8xx-3xx=0

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