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5x+2(x-3)=6(x-1)+x
We move all terms to the left:
5x+2(x-3)-(6(x-1)+x)=0
We multiply parentheses
5x+2x-(6(x-1)+x)-6=0
We calculate terms in parentheses: -(6(x-1)+x), so:We add all the numbers together, and all the variables
6(x-1)+x
We add all the numbers together, and all the variables
x+6(x-1)
We multiply parentheses
x+6x-6
We add all the numbers together, and all the variables
7x-6
Back to the equation:
-(7x-6)
7x-(7x-6)-6=0
We get rid of parentheses
7x-7x+6-6=0
We add all the numbers together, and all the variables
=0
x=0/1
x=0
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