5x+2(x-3)=4(x-5)-1

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Solution for 5x+2(x-3)=4(x-5)-1 equation: 



5x+2(x-3)=4(x-5)-1

We move all terms to the left:

5x+2(x-3)-(4(x-5)-1)=0

We multiply parentheses

5x+2x-(4(x-5)-1)-6=0



We calculate terms in parentheses: -(4(x-5)-1), so:

4(x-5)-1

We multiply parentheses

4x-20-1

We add all the numbers together, and all the variables

4x-21

Back to the equation:

-(4x-21)



We add all the numbers together, and all the variables

7x-(4x-21)-6=0

We get rid of parentheses

7x-4x+21-6=0

We add all the numbers together, and all the variables

3x+15=0

We move all terms containing x to the left, all other terms to the right

3x=-15

x=-15/3

x=-5

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