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5x+2(x-3)=4(x+1)+3x-6
We move all terms to the left:
5x+2(x-3)-(4(x+1)+3x-6)=0
We multiply parentheses
5x+2x-(4(x+1)+3x-6)-6=0
We calculate terms in parentheses: -(4(x+1)+3x-6), so:We add all the numbers together, and all the variables
4(x+1)+3x-6
We add all the numbers together, and all the variables
3x+4(x+1)-6
We multiply parentheses
3x+4x+4-6
We add all the numbers together, and all the variables
7x-2
Back to the equation:
-(7x-2)
7x-(7x-2)-6=0
We get rid of parentheses
7x-7x+2-6=0
We add all the numbers together, and all the variables
-4!=0
There is no solution for this equation
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