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5x+10=1/2(245-x)
We move all terms to the left:
5x+10-(1/2(245-x))=0
Domain of the equation: 2(245-x))!=0We add all the numbers together, and all the variables
x∈R
5x-(1/2(-1x+245))+10=0
We multiply all the terms by the denominator
5x*2(-1x+245))-(1+10*2(-1x+245))=0
Wy multiply elements
10x^2(-+20x(-=0
We use the square of the difference formula
10x^2(-20x(-=0
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