5x+1-(4/x)=0

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Solution for 5x+1-(4/x)=0 equation: 


D( x )

x = 0

x = 0

x = 0

x in (-oo:0) U (0:+oo)

5*x-(4/x)+1 = 0

5*x-4*x^-1+1 = 0

5*x^1-4*x^-1+1*x^0 = 0

(5*x^2+1*x^1-4*x^0)/(x^1) = 0 // * x^2

x^1*(5*x^2+1*x^1-4*x^0) = 0

x^1

5*x^2+x-4 = 0

5*x^2+x-4 = 0

DELTA = 1^2-(-4*4*5)

DELTA = 81

DELTA > 0

x = (81^(1/2)-1)/(2*5) or x = (-81^(1/2)-1)/(2*5)

x = 4/5 or x = -1

x in { -1, 4/5} 

x in { -1, 4/5 }

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