5x+1(3x+4)=6x(4x-2)

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Solution for 5x+1(3x+4)=6x(4x-2) equation: 



5x+1(3x+4)=6x(4x-2)

We move all terms to the left:

5x+1(3x+4)-(6x(4x-2))=0



We calculate terms in parentheses: -(6x(4x-2)), so:

6x(4x-2)

We multiply parentheses

24x^2-12x

Back to the equation:

-(24x^2-12x)



We get rid of parentheses

-24x^2+5x+1(3x+4)+12x=0

We add all the numbers together, and all the variables

-24x^2+17x+1(3x+4)=0

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