5x+(9x2)=13

Solution for 5x+(9x2)=13 equation:

5x+(9x^2)=13

We move all terms to the left:

5x+(9x^2)-(13)=0

determiningTheFunctionDomain
9x^2+5x-13=0

a = 9; b = 5; c = -13;
Δ = b2-4ac
Δ = 52-4·9·(-13)
Δ = 493
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(5)-\sqrt{493}}{2*9}=\frac{-5-\sqrt{493}}{18}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(5)+\sqrt{493}}{2*9}=\frac{-5+\sqrt{493}}{18}
$