5x+(5x2)=27

Solution for 5x+(5x2)=27 equation:

5x+(5x^2)=27

We move all terms to the left:

5x+(5x^2)-(27)=0

determiningTheFunctionDomain
5x^2+5x-27=0

a = 5; b = 5; c = -27;
Δ = b2-4ac
Δ = 52-4·5·(-27)
Δ = 565
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(5)-\sqrt{565}}{2*5}=\frac{-5-\sqrt{565}}{10}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(5)+\sqrt{565}}{2*5}=\frac{-5+\sqrt{565}}{10}
$