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5x*3x=48
We move all terms to the left:
5x*3x-(48)=0
Wy multiply elements
15x^2-48=0
a = 15; b = 0; c = -48;
Δ = b2-4ac
Δ = 02-4·15·(-48)
Δ = 2880
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{2880}=\sqrt{576*5}=\sqrt{576}*\sqrt{5}=24\sqrt{5}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-24\sqrt{5}}{2*15}=\frac{0-24\sqrt{5}}{30} =-\frac{24\sqrt{5}}{30} =-\frac{4\sqrt{5}}{5} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+24\sqrt{5}}{2*15}=\frac{0+24\sqrt{5}}{30} =\frac{24\sqrt{5}}{30} =\frac{4\sqrt{5}}{5} $
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