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5x(x-2)-3x=2(x-3)-16
We move all terms to the left:
5x(x-2)-3x-(2(x-3)-16)=0
We add all the numbers together, and all the variables
-3x+5x(x-2)-(2(x-3)-16)=0
We multiply parentheses
5x^2-3x-10x-(2(x-3)-16)=0
We calculate terms in parentheses: -(2(x-3)-16), so:We add all the numbers together, and all the variables
2(x-3)-16
We multiply parentheses
2x-6-16
We add all the numbers together, and all the variables
2x-22
Back to the equation:
-(2x-22)
5x^2-13x-(2x-22)=0
We get rid of parentheses
5x^2-13x-2x+22=0
We add all the numbers together, and all the variables
5x^2-15x+22=0
a = 5; b = -15; c = +22;
Δ = b2-4ac
Δ = -152-4·5·22
Δ = -215
Delta is less than zero, so there is no solution for the equation
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