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5x(x+6)-7(x+6)=0
We multiply parentheses
5x^2+30x-7x-42=0
We add all the numbers together, and all the variables
5x^2+23x-42=0
a = 5; b = 23; c = -42;
Δ = b2-4ac
Δ = 232-4·5·(-42)
Δ = 1369
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1369}=37$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(23)-37}{2*5}=\frac{-60}{10} =-6 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(23)+37}{2*5}=\frac{14}{10} =1+2/5 $
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