5x(4-2x)=20

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Solution for 5x(4-2x)=20 equation: 



5x(4-2x)=20

We move all terms to the left:

5x(4-2x)-(20)=0

We add all the numbers together, and all the variables

5x(-2x+4)-20=0

We multiply parentheses

-10x^2+20x-20=0

a = -10; b = 20; c = -20;
Δ = b2-4ac
Δ = 202-4·(-10)·(-20)
Δ = -400
Delta is less than zero, so there is no solution for the equation

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