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5x(3x+6)=60
We move all terms to the left:
5x(3x+6)-(60)=0
We multiply parentheses
15x^2+30x-60=0
a = 15; b = 30; c = -60;
Δ = b2-4ac
Δ = 302-4·15·(-60)
Δ = 4500
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{4500}=\sqrt{900*5}=\sqrt{900}*\sqrt{5}=30\sqrt{5}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(30)-30\sqrt{5}}{2*15}=\frac{-30-30\sqrt{5}}{30} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(30)+30\sqrt{5}}{2*15}=\frac{-30+30\sqrt{5}}{30} $
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