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5x(3x+150)=4730
We move all terms to the left:
5x(3x+150)-(4730)=0
We multiply parentheses
15x^2+750x-4730=0
a = 15; b = 750; c = -4730;
Δ = b2-4ac
Δ = 7502-4·15·(-4730)
Δ = 846300
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{846300}=\sqrt{100*8463}=\sqrt{100}*\sqrt{8463}=10\sqrt{8463}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(750)-10\sqrt{8463}}{2*15}=\frac{-750-10\sqrt{8463}}{30} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(750)+10\sqrt{8463}}{2*15}=\frac{-750+10\sqrt{8463}}{30} $
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