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5x(32-6x)=12
We move all terms to the left:
5x(32-6x)-(12)=0
We add all the numbers together, and all the variables
5x(-6x+32)-12=0
We multiply parentheses
-30x^2+160x-12=0
a = -30; b = 160; c = -12;
Δ = b2-4ac
Δ = 1602-4·(-30)·(-12)
Δ = 24160
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{24160}=\sqrt{16*1510}=\sqrt{16}*\sqrt{1510}=4\sqrt{1510}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(160)-4\sqrt{1510}}{2*-30}=\frac{-160-4\sqrt{1510}}{-60} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(160)+4\sqrt{1510}}{2*-30}=\frac{-160+4\sqrt{1510}}{-60} $
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