5x(2x-5)=-(-4x-5)

Solution for 5x(2x-5)=-(-4x-5) equation:

5x(2x-5)=-(-4x-5)

We move all terms to the left:

5x(2x-5)-(-(-4x-5))=0

We multiply parentheses

10x^2-25x-(-(-4x-5))=0


We calculate terms in parentheses: -(-(-4x-5)), so:

-(-4x-5)

We get rid of parentheses

4x+5

Back to the equation:

-(4x+5)


We get rid of parentheses

10x^2-25x-4x-5=0

We add all the numbers together, and all the variables

10x^2-29x-5=0

a = 10; b = -29; c = -5;
Δ = b2-4ac
Δ = -292-4·10·(-5)
Δ = 1041
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-29)-\sqrt{1041}}{2*10}=\frac{29-\sqrt{1041}}{20}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-29)+\sqrt{1041}}{2*10}=\frac{29+\sqrt{1041}}{20}
$