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5x(2x-3)-(x*8)=13
We move all terms to the left:
5x(2x-3)-(x*8)-(13)=0
We add all the numbers together, and all the variables
5x(2x-3)-(+x*8)-13=0
We multiply parentheses
10x^2-15x-(+x*8)-13=0
We get rid of parentheses
10x^2-15x-x*8-13=0
Wy multiply elements
10x^2-15x-8x-13=0
We add all the numbers together, and all the variables
10x^2-23x-13=0
a = 10; b = -23; c = -13;
Δ = b2-4ac
Δ = -232-4·10·(-13)
Δ = 1049
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-23)-\sqrt{1049}}{2*10}=\frac{23-\sqrt{1049}}{20} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-23)+\sqrt{1049}}{2*10}=\frac{23+\sqrt{1049}}{20} $
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