5x(2x-1)+10=7(2x-1)

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Solution for 5x(2x-1)+10=7(2x-1) equation: 



5x(2x-1)+10=7(2x-1)

We move all terms to the left:

5x(2x-1)+10-(7(2x-1))=0

We multiply parentheses

10x^2-5x-(7(2x-1))+10=0



We calculate terms in parentheses: -(7(2x-1)), so:

7(2x-1)

We multiply parentheses

14x-7

Back to the equation:

-(14x-7)



We get rid of parentheses

10x^2-5x-14x+7+10=0

We add all the numbers together, and all the variables

10x^2-19x+17=0

a = 10; b = -19; c = +17;
Δ = b2-4ac
Δ = -192-4·10·17
Δ = -319
Delta is less than zero, so there is no solution for the equation

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