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5x(2x+1)=12x-3
We move all terms to the left:
5x(2x+1)-(12x-3)=0
We multiply parentheses
10x^2+5x-(12x-3)=0
We get rid of parentheses
10x^2+5x-12x+3=0
We add all the numbers together, and all the variables
10x^2-7x+3=0
a = 10; b = -7; c = +3;
Δ = b2-4ac
Δ = -72-4·10·3
Δ = -71
Delta is less than zero, so there is no solution for the equation
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