5x(2a+c)=4(x+c)

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Solution for 5x(2a+c)=4(x+c) equation:


Simplifying
5x(2a + c) = 4(x + c)
(2a * 5x + c * 5x) = 4(x + c)
(10ax + 5cx) = 4(x + c)

Reorder the terms:
10ax + 5cx = 4(c + x)
10ax + 5cx = (c * 4 + x * 4)
10ax + 5cx = (4c + 4x)

Solving
10ax + 5cx = 4c + 4x

Solving for variable 'a'.

Move all terms containing a to the left, all other terms to the right.

Add '-5cx' to each side of the equation.
10ax + 5cx + -5cx = 4c + -5cx + 4x

Combine like terms: 5cx + -5cx = 0
10ax + 0 = 4c + -5cx + 4x
10ax = 4c + -5cx + 4x

Divide each side by '10x'.
a = 0.4cx-1 + -0.5c + 0.4

Simplifying
a = 0.4cx-1 + -0.5c + 0.4

Reorder the terms:
a = 0.4 + -0.5c + 0.4cx-1

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