5x(2+4x)=25x

Solution for 5x(2+4x)=25x equation:

5x(2+4x)=25x

We move all terms to the left:

5x(2+4x)-(25x)=0

We add all the numbers together, and all the variables

5x(4x+2)-25x=0

We add all the numbers together, and all the variables

-25x+5x(4x+2)=0

We multiply parentheses

20x^2-25x+10x=0

We add all the numbers together, and all the variables

20x^2-15x=0

a = 20; b = -15; c = 0;
Δ = b2-4ac
Δ = -152-4·20·0
Δ = 225
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{225}=15$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-15)-15}{2*20}=\frac{0}{40}
=0
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-15)+15}{2*20}=\frac{30}{40}
=3/4
$