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5x(10x+5)=(6x+5x)
We move all terms to the left:
5x(10x+5)-((6x+5x))=0
We add all the numbers together, and all the variables
5x(10x+5)-((+11x))=0
We multiply parentheses
50x^2+25x-((+11x))=0
We calculate terms in parentheses: -((+11x)), so:We add all the numbers together, and all the variables
(+11x)
We get rid of parentheses
11x
Back to the equation:
-(11x)
50x^2+14x=0
a = 50; b = 14; c = 0;
Δ = b2-4ac
Δ = 142-4·50·0
Δ = 196
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{196}=14$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(14)-14}{2*50}=\frac{-28}{100} =-7/25 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(14)+14}{2*50}=\frac{0}{100} =0 $
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