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5x(1+3x)=10
We move all terms to the left:
5x(1+3x)-(10)=0
We add all the numbers together, and all the variables
5x(3x+1)-10=0
We multiply parentheses
15x^2+5x-10=0
a = 15; b = 5; c = -10;
Δ = b2-4ac
Δ = 52-4·15·(-10)
Δ = 625
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{625}=25$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(5)-25}{2*15}=\frac{-30}{30} =-1 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(5)+25}{2*15}=\frac{20}{30} =2/3 $
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