# 5x^2/3+61=121

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## Solution for 5x^2/3+61=121 equation:

5x^2/3+61=121
We move all terms to the left:
5x^2/3+61-(121)=0
We add all the numbers together, and all the variables
5x^2/3-60=0
We multiply all the terms by the denominator

5x^2-60*3=0
We add all the numbers together, and all the variables
5x^2-180=0
a = 5; b = 0; c = -180;Δ = b2-4acΔ = 02-4·5·(-180)Δ = 3600The delta value is higher than zero, so the equation has two solutionsWe use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{3600}=60$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-60}{2*5}=\frac{-60}{10} =-6$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+60}{2*5}=\frac{60}{10} =6$

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