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5x^2/3+61=121

We move all terms to the left:

5x^2/3+61-(121)=0

We add all the numbers together, and all the variables

5x^2/3-60=0

We multiply all the terms by the denominator

5x^2-60*3=0

We add all the numbers together, and all the variables

5x^2-180=0

a = 5; b = 0; c = -180;

Δ = b^{2}-4ac

Δ = 0^{2}-4·5·(-180)

Δ = 3600

The delta value is higher than zero, so the equation has two solutions

We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{3600}=60$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-60}{2*5}=\frac{-60}{10} =-6 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+60}{2*5}=\frac{60}{10} =6 $

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