5w(5w+12)=-30

Solution for 5w(5w+12)=-30 equation:

5w(5w+12)=-30

We move all terms to the left:

5w(5w+12)-(-30)=0

We add all the numbers together, and all the variables

5w(5w+12)+30=0

We multiply parentheses

25w^2+60w+30=0

a = 25; b = 60; c = +30;
Δ = b2-4ac
Δ = 602-4·25·30
Δ = 600
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{600}=\sqrt{100*6}=\sqrt{100}*\sqrt{6}=10\sqrt{6}$
$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(60)-10\sqrt{6}}{2*25}=\frac{-60-10\sqrt{6}}{50}
$
$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(60)+10\sqrt{6}}{2*25}=\frac{-60+10\sqrt{6}}{50}
$