5v2-47v+56=0

Solution for 5v2-47v+56=0 equation:

5v^2-47v+56=0

a = 5; b = -47; c = +56;
Δ = b2-4ac
Δ = -472-4·5·56
Δ = 1089
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1089}=33$
$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-47)-33}{2*5}=\frac{14}{10}
=1+2/5
$
$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-47)+33}{2*5}=\frac{80}{10}
=8
$