If it's not what You are looking for type in the equation solver your own equation and let us solve it.
5v^2-20v=0
a = 5; b = -20; c = 0;
Δ = b2-4ac
Δ = -202-4·5·0
Δ = 400
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{400}=20$$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-20)-20}{2*5}=\frac{0}{10} =0 $$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-20)+20}{2*5}=\frac{40}{10} =4 $
| -9x-8=-15x-32 | | 2x=10+x+20=180 | | 2x=10+x+20 | | 2x-5/4=3x+1/5 | | 4x-12=8x+24= | | 97+8x=99+7x | | 24*(x+3)+23*(4-x)=210 | | 4x+14=2/3x+19 | | f(3)=2(3)^2-3(3)-5 | | -(16/19)y=-(20/38) | | .15x+x=252 | | 3-(5x-4)-9x=21 | | 2/3+1/3x=2x | | 3m+5(m-1)=7 | | 6x+2(-14+4)=3x-7 | | 9-4n=10-5 | | 4x+34=6x+6 | | .15x+x=244 | | -8x-4=7x+2 | | 4(2a-3)=4 | | -7v-5=(v+5) | | 5x+(-3)=7x-15 | | 4y+5=7-2y | | 3(x-2)+2x=-11 | | X-0.145x=3.603 | | (5x+12)^2=64 | | 8w+6(w+5)=16 | | 4x.05(4x)=46.2 | | 6n-1=5n+5 | | 225=25x-18 | | 208=-x+131 | | 0=-16t2+72t-45 |