5t2+20t+25=0

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Solution for 5t2+20t+25=0 equation: 



5t^2+20t+25=0

a = 5; b = 20; c = +25;
Δ = b2-4ac
Δ = 202-4·5·25
Δ = -100
Delta is less than zero, so there is no solution for the equation

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