5t-10/t-5/t-2/2

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Solution for 5t-10/t-5/t-2/2 equation: 


D( t )

t = 0

t = 0

t = 0

t in (-oo:0) U (0:+oo)

5*t-(10/t)-(5/t)-(2/2) = 0

5*t-10*t^-1-5*t^-1-1 = 0

5*t^1-15*t^-1-1*t^0 = 0

(5*t^2-1*t^1-15*t^0)/(t^1) = 0 // * t^2

t^1*(5*t^2-1*t^1-15*t^0) = 0

t^1

5*t^2-t-15 = 0

5*t^2-t-15 = 0

DELTA = (-1)^2-(-15*4*5)

DELTA = 301

DELTA > 0

t = (301^(1/2)+1)/(2*5) or t = (1-301^(1/2))/(2*5)

t = (301^(1/2)+1)/10 or t = (1-301^(1/2))/10

t in { (1-301^(1/2))/10, (301^(1/2)+1)/10} 

t in { (1-301^(1/2))/10, (301^(1/2)+1)/10 }

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