5t+6(4+-3)=40

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Solution for 5t+6(4+-3)=40 equation: 



5t+6(4+-3)=40

We move all terms to the left:

5t+6(4+-3)-(40)=0

determiningTheFunctionDomain
5t-40+6(4+-3)=0

We add all the numbers together, and all the variables

5t-40+61=0

We add all the numbers together, and all the variables

5t+21=0

We move all terms containing t to the left, all other terms to the right

5t=-21

t=-21/5

t=-4+1/5

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