5t+2(t+3)-4t=4(t+1)-(t-2)

Solution for 5t+2(t+3)-4t=4(t+1)-(t-2) equation:

5t+2(t+3)-4t=4(t+1)-(t-2)

We simplify the equation to the form, which is simple to understand 
5t+2(t+3)-4t=4(t+1)-(t-2)

Reorder the terms in parentheses
5t+(+2t+6)-4t=4*(t+1)-(t-2)

Remove unnecessary parentheses
+5t+2t+6-4t=+4+*(+t+1+)-(+t-2+)

Reorder the terms in parentheses
5t+2t+6-4t=+(+4t+4)-(t-2)

Remove unnecessary parentheses
+5t+2t+6-4t=+4t+4-(+t-2+)

Remove unnecessary parentheses
5t+2t+6-4t=+4t+4-1t+2

We move all terms containing t to the left and all other terms to the right. 
+5t+2t-4t-4t+1t=+4+2-6

We simplify left and right side of the equation. 
t=0

0=0

This equation is an identity, so all real numbers are solutions.