5sin(2x)+7cos(x)=0

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Solution for 5sin(2x)+7cos(x)=0 equation:


Simplifying
5sin(2x) + 7cos(x) = 0

Remove parenthesis around (2x)
5ins * 2x + 7cos(x) = 0

Reorder the terms for easier multiplication:
5 * 2ins * x + 7cos(x) = 0

Multiply 5 * 2
10ins * x + 7cos(x) = 0

Multiply ins * x
10insx + 7cos(x) = 0

Multiply cos * x
10insx + 7cosx = 0

Reorder the terms:
7cosx + 10insx = 0

Solving
7cosx + 10insx = 0

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Add '-10insx' to each side of the equation.
7cosx + 10insx + -10insx = 0 + -10insx

Combine like terms: 10insx + -10insx = 0
7cosx + 0 = 0 + -10insx
7cosx = 0 + -10insx
Remove the zero:
7cosx = -10insx

Divide each side by '7osx'.
c = -1.428571429ino-1

Simplifying
c = -1.428571429ino-1

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