5s+2(2-d)=3(1+d)+1

Solution for 5s+2(2-d)=3(1+d)+1 equation:

Simplifying
5s + 2(2 + -1d) = 3(1 + d) + 1
5s + (2 * 2 + -1d * 2) = 3(1 + d) + 1
5s + (4 + -2d) = 3(1 + d) + 1

Reorder the terms:
4 + -2d + 5s = 3(1 + d) + 1
4 + -2d + 5s = (1 * 3 + d * 3) + 1
4 + -2d + 5s = (3 + 3d) + 1

Reorder the terms:
4 + -2d + 5s = 3 + 1 + 3d

Combine like terms: 3 + 1 = 4
4 + -2d + 5s = 4 + 3d

Add '-4' to each side of the equation.
4 + -2d + -4 + 5s = 4 + -4 + 3d

Reorder the terms:
4 + -4 + -2d + 5s = 4 + -4 + 3d

Combine like terms: 4 + -4 = 0
0 + -2d + 5s = 4 + -4 + 3d
-2d + 5s = 4 + -4 + 3d

Combine like terms: 4 + -4 = 0
-2d + 5s = 0 + 3d
-2d + 5s = 3d

Solving
-2d + 5s = 3d

Solving for variable 'd'.

Move all terms containing d to the left, all other terms to the right.

Add '-3d' to each side of the equation.
-2d + -3d + 5s = 3d + -3d

Combine like terms: -2d + -3d = -5d
-5d + 5s = 3d + -3d

Combine like terms: 3d + -3d = 0
-5d + 5s = 0

Add '-5s' to each side of the equation.
-5d + 5s + -5s = 0 + -5s

Combine like terms: 5s + -5s = 0
-5d + 0 = 0 + -5s
-5d = 0 + -5s
Remove the zero:
-5d = -5s

Divide each side by '-5'.
d = s

Simplifying
d = s