5r-(r+3)=1+2(t-3)

Solution for 5r-(r+3)=1+2(t-3) equation:

Simplifying
5r + -1(r + 3) = 1 + 2(t + -3)

Reorder the terms:
5r + -1(3 + r) = 1 + 2(t + -3)
5r + (3 * -1 + r * -1) = 1 + 2(t + -3)
5r + (-3 + -1r) = 1 + 2(t + -3)

Reorder the terms:
-3 + 5r + -1r = 1 + 2(t + -3)

Combine like terms: 5r + -1r = 4r
-3 + 4r = 1 + 2(t + -3)

Reorder the terms:
-3 + 4r = 1 + 2(-3 + t)
-3 + 4r = 1 + (-3 * 2 + t * 2)
-3 + 4r = 1 + (-6 + 2t)

Combine like terms: 1 + -6 = -5
-3 + 4r = -5 + 2t

Solving
-3 + 4r = -5 + 2t

Solving for variable 'r'.

Move all terms containing r to the left, all other terms to the right.

Add '3' to each side of the equation.
-3 + 3 + 4r = -5 + 3 + 2t

Combine like terms: -3 + 3 = 0
0 + 4r = -5 + 3 + 2t
4r = -5 + 3 + 2t

Combine like terms: -5 + 3 = -2
4r = -2 + 2t

Divide each side by '4'.
r = -0.5 + 0.5t

Simplifying
r = -0.5 + 0.5t