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5q-10=2-(4-q)
We move all terms to the left:
5q-10-(2-(4-q))=0
We add all the numbers together, and all the variables
5q-(2-(-1q+4))-10=0
We calculate terms in parentheses: -(2-(-1q+4)), so:We get rid of parentheses
2-(-1q+4)
determiningTheFunctionDomain -(-1q+4)+2
We get rid of parentheses
1q-4+2
We add all the numbers together, and all the variables
q-2
Back to the equation:
-(q-2)
5q-q+2-10=0
We add all the numbers together, and all the variables
4q-8=0
We move all terms containing q to the left, all other terms to the right
4q=8
q=8/4
q=2
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