5p2-11p+6=0

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Solution for 5p2-11p+6=0 equation: 



5p^2-11p+6=0

a = 5; b = -11; c = +6;
Δ = b2-4ac
Δ = -112-4·5·6
Δ = 1
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1}=1$


$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-11)-1}{2*5}=\frac{10}{10}
=1
$


$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-11)+1}{2*5}=\frac{12}{10}
=1+1/5
$

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