5p+12=17-4((p/2)+1)

Solution for 5p+12=17-4((p/2)+1) equation:

5p+12=17-4((p/2)+1)

We move all terms to the left:

5p+12-(17-4((p/2)+1))=0

We add all the numbers together, and all the variables

5p-(17-4((+p/2)+1))+12=0

We multiply all the terms by the denominator


5p*2)+1))-(17-4((+p+12*2)+1))=0

We add all the numbers together, and all the variables

5p*2)+1))-(17-4((p+24)+1))=0

We add all the numbers together, and all the variables

5p*2)+1))-(17-4((p=0

Wy multiply elements

10p^2=0

a = 10; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·10·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$p=\frac{-b}{2a}=\frac{0}{20}=0$