5n=3+3(n-1)+n

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Solution for 5n=3+3(n-1)+n equation: 



5n=3+3(n-1)+n

We move all terms to the left:

5n-(3+3(n-1)+n)=0



We calculate terms in parentheses: -(3+3(n-1)+n), so:

3+3(n-1)+n

determiningTheFunctionDomain
3(n-1)+n+3

We add all the numbers together, and all the variables

n+3(n-1)+3

We multiply parentheses

n+3n-3+3

We add all the numbers together, and all the variables

4n

Back to the equation:

-(4n)



We add all the numbers together, and all the variables

n=0

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