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5n^2+9n-72=0
a = 5; b = 9; c = -72;
Δ = b2-4ac
Δ = 92-4·5·(-72)
Δ = 1521
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1521}=39$$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(9)-39}{2*5}=\frac{-48}{10} =-4+4/5 $$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(9)+39}{2*5}=\frac{30}{10} =3 $
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