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5n^2+6n-104=0
a = 5; b = 6; c = -104;
Δ = b2-4ac
Δ = 62-4·5·(-104)
Δ = 2116
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{2116}=46$$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(6)-46}{2*5}=\frac{-52}{10} =-5+1/5 $$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(6)+46}{2*5}=\frac{40}{10} =4 $
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