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5n^2+18n+9=0
a = 5; b = 18; c = +9;
Δ = b2-4ac
Δ = 182-4·5·9
Δ = 144
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{144}=12$$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(18)-12}{2*5}=\frac{-30}{10} =-3 $$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(18)+12}{2*5}=\frac{-6}{10} =-3/5 $
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