5n2+11n+2=0

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Solution for 5n2+11n+2=0 equation: 



5n^2+11n+2=0

a = 5; b = 11; c = +2;
Δ = b2-4ac
Δ = 112-4·5·2
Δ = 81
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{81}=9$


$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(11)-9}{2*5}=\frac{-20}{10}
=-2
$


$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(11)+9}{2*5}=\frac{-2}{10}
=-1/5
$

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