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5n-9/n+6=2
We move all terms to the left:
5n-9/n+6-(2)=0
Domain of the equation: n!=0We add all the numbers together, and all the variables
n∈R
5n-9/n+4=0
We multiply all the terms by the denominator
5n*n+4*n-9=0
We add all the numbers together, and all the variables
4n+5n*n-9=0
Wy multiply elements
5n^2+4n-9=0
a = 5; b = 4; c = -9;
Δ = b2-4ac
Δ = 42-4·5·(-9)
Δ = 196
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{196}=14$$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(4)-14}{2*5}=\frac{-18}{10} =-1+4/5 $$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(4)+14}{2*5}=\frac{10}{10} =1 $
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