5n(3+2n)-3n(n+1)=7n2+n

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Solution for 5n(3+2n)-3n(n+1)=7n2+n equation: 



5n(3+2n)-3n(n+1)=7n^2+n

We move all terms to the left:

5n(3+2n)-3n(n+1)-(7n^2+n)=0

We add all the numbers together, and all the variables

5n(2n+3)-3n(n+1)-(7n^2+n)=0

We multiply parentheses

10n^2-3n^2+15n-3n-(7n^2+n)=0

We get rid of parentheses

10n^2-3n^2-7n^2+15n-3n-n=0

We add all the numbers together, and all the variables

11n=0

n=0/11

n=0

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