5n^2+11n-9718=0

Solution for 5n^2+11n-9718=0 equation:

5n^2+11n-9718=0

a = 5; b = 11; c = -9718;
Δ = b2-4ac
Δ = 112-4·5·(-9718)
Δ = 194481
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{194481}=441$
$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(11)-441}{2*5}=\frac{-452}{10}
=-45+1/5
$
$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(11)+441}{2*5}=\frac{430}{10}
=43
$