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5m=8/2m-6
We move all terms to the left:
5m-(8/2m-6)=0
Domain of the equation: 2m-6)!=0We get rid of parentheses
m∈R
5m-8/2m+6=0
We multiply all the terms by the denominator
5m*2m+6*2m-8=0
Wy multiply elements
10m^2+12m-8=0
a = 10; b = 12; c = -8;
Δ = b2-4ac
Δ = 122-4·10·(-8)
Δ = 464
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{464}=\sqrt{16*29}=\sqrt{16}*\sqrt{29}=4\sqrt{29}$$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(12)-4\sqrt{29}}{2*10}=\frac{-12-4\sqrt{29}}{20} $$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(12)+4\sqrt{29}}{2*10}=\frac{-12+4\sqrt{29}}{20} $
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