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5m^2+40m+75=0
a = 5; b = 40; c = +75;
Δ = b2-4ac
Δ = 402-4·5·75
Δ = 100
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{100}=10$$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(40)-10}{2*5}=\frac{-50}{10} =-5 $$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(40)+10}{2*5}=\frac{-30}{10} =-3 $
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