5m+2(m+3)-3=3(m-4)+15+4m

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Solution for 5m+2(m+3)-3=3(m-4)+15+4m equation: 



5m+2(m+3)-3=3(m-4)+15+4m

We move all terms to the left:

5m+2(m+3)-3-(3(m-4)+15+4m)=0

We multiply parentheses

5m+2m-(3(m-4)+15+4m)+6-3=0



We calculate terms in parentheses: -(3(m-4)+15+4m), so:

3(m-4)+15+4m

determiningTheFunctionDomain
3(m-4)+4m+15

We add all the numbers together, and all the variables

4m+3(m-4)+15

We multiply parentheses

4m+3m-12+15

We add all the numbers together, and all the variables

7m+3

Back to the equation:

-(7m+3)



We add all the numbers together, and all the variables

7m-(7m+3)+3=0

We get rid of parentheses

7m-7m-3+3=0

We add all the numbers together, and all the variables

=0

m=0/1

m=0

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