5m+0=3(m-5)+7

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Solution for 5m+0=3(m-5)+7 equation: 



5m+0=3(m-5)+7

We move all terms to the left:

5m+0-(3(m-5)+7)=0

We add all the numbers together, and all the variables

5m-(3(m-5)+7)=0



We calculate terms in parentheses: -(3(m-5)+7), so:

3(m-5)+7

We multiply parentheses

3m-15+7

We add all the numbers together, and all the variables

3m-8

Back to the equation:

-(3m-8)



We get rid of parentheses

5m-3m+8=0

We add all the numbers together, and all the variables

2m+8=0

We move all terms containing m to the left, all other terms to the right

2m=-8

m=-8/2

m=-4

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